replaceOrAppend

替换数组中的项目，如果不匹配则追加

使用方法

给定一个项目数组、一个项目和一个身份函数，返回一个新数组，其中项目在现有项目的索引处被替换（如果存在），否则在末尾追加。

import * as _ from "radashi";

const fish = [
  {
    name: "Marlin",
    weight: 105,
  },
  {
    name: "Salmon",
    weight: 19,
  },
  {
    name: "Trout",
    weight: 13,
  },
];

const salmon = {
  name: "Salmon",
  weight: 22,
};

const sockeye = {
  name: "Sockeye",
  weight: 8,
};

_.replaceOrAppend(fish, salmon, (f) => f.name === "Salmon"); // => [marlin, salmon (weight:22), trout]
_.replaceOrAppend(fish, sockeye, (f) => f.name === "Sockeye"); // => [marlin, salmon, trout, sockeye]